\(\therefore\) The question converts to cosec-1(-1)
Now,
The range of principal value of cosec-1 is
\([\frac{-\pi}2,\frac{\pi}2]\) - {0} and cosec\((\frac{-\pi}2)=-1\)
Therefore, the principal value of cosec-1(2cos\(\frac{2\pi}3\)) is \(\frac{-\pi}2.\)