We know that sin-1 (sin θ) = π – θ,
if θ ∈ [π/2, 3π/2] and cos-1 (cos θ) = θ, if θ ∈ [0, π]
Given \(cos^{-1}(cos\frac{2\pi}{3})+sin^{-1}(sin\frac{2\pi}{3}).\)
\(=\frac{2\pi}{3}+(\pi-\frac{2\pi}{3})\)
= π
\(\therefore \)\(cos^{-1}(cos\frac{2\pi}{3})+sin^{-1}(sin\frac{2\pi}{3})\)\(=\pi\)