Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
609 views
in Algebraic Expressions by (36.4k points)
closed by

Simplify the following using the identities:

(i) \(\frac{58^2-42^2}{16}\)

(ii) 178 x 178 - 22 x 22

(iii) \(\frac{198\times 198-102\times 102}{96}\)

(iv) 1.73 x 1.73 - 0.27 x 0.27

(v) \(\frac{8.63\times 8.63-1.37\times 1.37}{0.726}\)

1 Answer

+1 vote
by (38.0k points)
selected by
 
Best answer

(i) \(\frac{58^2-42^2}{16}\)

\(\frac{(58-42)(58-42)}{4\times 4}\)

\(\frac{16(100)}{16}\)

= 100

(ii) 178 x 178 - 22 x 22

(178)2 – (22)2 

= (178 + 22) (178 – 22) 

= 200 × 156 

= 31200

(iii) \(\frac{198\times 198-102\times 102}{96}\)

\(\frac{(198-102)(198+102)}{96}\)

\(\frac{96\times 300}{96}\)

= 300

(iv) 1.73 x 1.73 - 0.27 x 0.27

(1.73) – (0.27)

= (1.73 + 0.27) (1.73 – 0.27) 

= 2 (1.46) 

= 2.92

(v) \(\frac{8.63\times 8.63-1.37\times 1.37}{0.726}\)

\(\frac{(8.63+1.37)(8.63-1.37)}{0.726}\)

\(\frac{10\times 7.26}{0.726}\)

 = 100

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...