Use app×
QUIZARD
QUIZARD
JEE MAIN 2026 Crash Course
NEET 2026 Crash Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.5k views
in Determinants by (27.0k points)
closed by

Without expanding, show that the value of each of the following determinants is zero :

\(\begin{vmatrix} cos(x+y)& -sin(x+y) & cos\,2y \\[0.3em] sinx & -cos\,x& sin\,y \\[0.3em] -cos\,x& sin\,x & -cos\,y\end{vmatrix}\)

1 Answer

+1 vote
by (27.4k points)
selected by
 
Best answer

Let Δ = \(\begin{vmatrix} cos(x+y)& -sin(x+y) & cos\,2y \\[0.3em] sinx & -cos\,x& sin\,y \\[0.3em] -cos\,x& sin\,x & -cos\,y\end{vmatrix}\)

Multiplying R2 with sin y and R3 with cos y we get,

As, 

R1 = R2 hence determinant is zero.

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...