Given : A die is tossed twice and ‘Getting a number greater than 4 ’ is considered a success.
To find : probability distribution of the number of successes and mean (μ) and variance (σ2)
Formula used :
When a die is tossed 4 times,
Total possible outcomes = 62 = 36
Getting a doublet is considered as a success
The possible doublets are (1,1) , (2,2) , (3,3) , (4,4) , (5,5) , (6,6)
Let p be the probability of success,
since the die is thrown 4 times, n = 4
x can take the values of 1,2,3,4
The probability distribution table is as follows,
The probability distribution table is as follows,
Mean = \(\frac{2}{3}\)
Variance = \(\frac{5}{9}\)