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in Matrices by (25.8k points)
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Find the matrix X satisfying the equation:

\(\begin{bmatrix}2&1\\5&3\end{bmatrix}X\begin{bmatrix}5&3\\3&2\end{bmatrix}\)\(=\begin{bmatrix}1&0\\0&1\end{bmatrix}.\)

1 Answer

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Best answer

 \(A=\begin{bmatrix}2&1\\5&3\end{bmatrix}\)\(B=\begin{bmatrix}5&3\\3&2\end{bmatrix}\)\(C=\begin{bmatrix}1&0\\0&1\end{bmatrix}\)

Then The given equations becomes as

AXB = I

= X = A-1 B–1

|A| = 6 – 5 = 1

|B| = 10 – 9 = 1

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