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If \(\frac{3}{5}\) of a number exceeds its \(\frac{2}{7}\) by \(44\) , find the number.

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Let the number be x

\(\frac{3}{5}\) of x \(=\frac{3}{5}\text{x}\)

\(\frac{2}{7}\) of x \(=\frac{2}{7}\text{x}\)

According to the question,

\(\frac{3}{5}\text{x}-\frac{2}{7}\text{x}=44\)

\(\Rightarrow\) \(\frac{3\text{x}\times7-2\text{x}\times5}{35}=44\) 

\(\Rightarrow\) \(\frac{21\text{x}-10\text{x}}{35}=44\)

\(\Rightarrow\) \(\frac{11}{35}\times\text{x}=44\)

\(\Rightarrow\) \(\text{x}=44\div\frac{11}{35}\)

\(\Rightarrow\) \(\text{x}=44\times\frac{35}{11}\)

\(\Rightarrow\) \(\text{x}=\frac{1540}{11}\)

\(\Rightarrow\) \(\text{x}=140\)

The number is 140

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