Question

Ravish wanted to make a temporary shelter for his car by making a box-like structure with tarpaulin that covers all the four sides and the top of the car (with the front face as a flap which can be rolled up). Assuming that the stitching margins are very small, and therefore negligible, how much tarpaulin would be required to make the shelter of height 2.5 m with base dimensions 4 m × 3 m?

Answer 1

Given,

Height of shelter = 2.5 m

Base dimensions = l × b = 4m × 3m

So, area of tarapaulin needed = lateral surface area of shelter +area of roof

= 2(l + b)h + l × b

= 2(4 + 3)2.5 +12 = 47 m²