Class interval |
Frequency |
Cumulative frequency |
0 - 10 |
10 |
10 |
10 - 20 |
20 |
30 |
20 - 30 |
f1 |
30 + f1 (F) |
30 - 40 |
40 (f) |
70 + f1 |
40 - 50 |
f2 |
70 + f1 + f2 |
50 - 60 |
25 |
95 + f1 + f2 |
60 - 70 |
15 |
110 + f1 + f2 |
|
N = 170 |
|
Given,
Median = 35
The median class = 30 - 40
l = 30, h = 10, f = 40 and F = 30 + f1
Median = l + \(\frac{\frac{N}{2}-F}{f}\)
\(30=30+\frac{85-(30+f_1)}{40}\times 10\)
\(5=\frac{55-f_1}{4}\)
f1 = 55 – 20 = 35
Given,
Sum of frequencies = 170
= 10 + 20 + f1 + 40 + f2 + 25 + 15 = 170
= 10 + 20 + 35 + 40 + f2 + 25 + 15 = 170
= f2 = 170 – 145 = 25
Therefore,
f1 = 35 and f2 = 25