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Solve the following quadratic equations by factorization:

\((x - 5)(x- 6) =\frac{25}{(24)^{2}}\)

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In factorization, we write the middle term of the quadratic equation either as a sum of two numbers or difference of two numbers such that the equation can be factorized.

\((x - 5)(x-6)=\frac{25}{(24)^{2}}\)

⇒ x2 – 11x + 30 = 25/(24)2 

⇒ x2 – 11x + 121/4 – 121/4 + 30 = 25/(24)

⇒ x2 – 11x + 121/4 = 25/(24)2 + 1/4 

⇒ x2 – 11x + 121/4 = 676/(4 × 242

⇒ (x – 11/2)2 = (13/24)2

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