Since in an equilateral triangle, orthocenter and centroid coincide, therefore the position vector of centroid is \(\vec 0.\)
Also, the position vector of centroid G( \(\vec g\)) can be defined as \(\cfrac{\vec a+\vec b+\vec c}3\)
Therefore, \(\cfrac{\vec a+\vec b+\vec c}3\) = \(\vec 0\) hence \(\vec a+\vec b+\vec c=\vec 0\)