Given that,
radius of spherical ball = 3 cm
We know that, Volume of the sphere = \(\frac{4}{3}πr^3\)
So,
its volume, v = \(\frac{4}{3}π(3)^3\)
The spherical ball of radius 3 cm is melted and recast into three spherical balls.
Let the radius of the third ball be r.
Then, volume of third spherical ball =\(\frac{4}{3}π(r)^3\)
Volume of first ball = \(\frac{4}{3}π(1.5)^3\)
Volume of second ball = \(\frac{4}{3}π(2)^3\)
The volume of the original spherical ball is equal to that of the total volumes of the three balls.
⇒ r = 2.5 cm
Thus,
diameter = 5 cm
