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Find [a b c], when vectors a = i - 2j + 3k, b = 2i + j - k and c = j + k

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Formula:-

Given: -

Now, using

= 1(1 + 1) + 2(2 + 0) + 3(2 – 0)

= 2 + 4 + 6 = 12

therefore,

\([\vec a,\,\vec b,\vec c]=12\)

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