The given system of equations can be written as
(2a – 1) x + 3y = 5
⇒(2a – 1) x + 3y – 5 = 0 ….(i)
and 3x + (b – 1)y = 2
⇒3x + (b – 1)y – 2 = 0 ….(ii)
These equations are of the following form:
a1x+b1y+c1 = 0, a2x+b2y+c2 = 0
where, a1 = (2a – 1), b1= 3, c1 = -5 and a2 = 3, b2 = (b – 1), c2 = -2
For an infinite number of solutions, we must have:
