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Find the values of a and b for which the system of linear equations has an infinite number of solutions: 

(2a – 1) x + 3y = 5, 

3x + (b – 1)y = 2.

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The given system of equations can be written as 

(2a – 1) x + 3y = 5 

⇒(2a – 1) x + 3y – 5 = 0 ….(i) 

and 3x + (b – 1)y = 2 

⇒3x + (b – 1)y – 2 = 0 ….(ii) 

These equations are of the following form:

a1x+b1y+c1 = 0, a2x+b2y+c2 = 0 

where, a1 = (2a – 1), b1= 3, c1 = -5 and a2 = 3, b2 = (b – 1), c2 = -2 

For an infinite number of solutions, we must have:

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