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Find the values of a and b for which the system of linear equations has an infinite number of solutions: 

2x + 3y = 7, (a + b)x + (2a - b)y = 21

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The given system of equations can be written as 

2x + 3y - 7 = 0 ….(i) 

(a + b)x + (2a - b)y – 21 = 0 ….(ii) 

This system is of the form: 

a1x+b1y+c1 = 0, a2x+b2y+c2 = 0 

where, a1 = 2, b1= 3, c1 = -7 and a2 = a + b, b2 = 2a - b, c2 = – 21 

For the given system of linear equations to have an infinite number of solutions, we must have:

Now substituting a = 5 in a + b = 6, we have 

5 + b = 6 ⇒ b = 6 – 5 = 1 

Hence, a = 5 and b = 1.

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