Given,
1/(|x|-3)≤1/2
We know that,
If we take reciprocal of any inequality we need to change the inequality as well.
Also,
|x|–3 ≠ 0
⇒ |x|>3 or |x|<3
For |x|<3
⇒ –3 < x < 3
⇒ x ∈ (–3, 3) …(1)
∴ The equation can be re–written as –
|x|–3+3 ≥ 2
Adding 2 both the sides, we get –
|x|–3+3≥ 2+3
⇒ |x| ≥ 5
We know that,
|x |≥a ⟺ x ≤ –a or x ≥ a
Here,
a = 5
⇒ x ≤ –5 or x ≥ 5
⇒ x ∈ (–∞,–5 ] or x ∈ [5, ∞) …(2)
⇒ x ∈ (–∞,–5 ] ⋃ (–3, 3) ⋃ [5, ∞)
(From 1 and 2)
We can verify the answers using graph as well.
