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निम्न को सरल कीजिए ।
`(7^(1//5))/(7^(1//3))`

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यहाँ
`(i) 2^(2//3)*2^(1//3)=2^((2)/(3)+(1)/(3))=2^(3//3)=2^(1)=2`.
`(ii) (3^(1//5))^(4)=3^(4//5)`
`(iii) (7^(1//5))/(7^(1//3))=7^((1)/(5)-(1)/(3))=7^(-2//15)`
`(iv) 13^(1//5)*17^(1//5)=(13xx17)^(1//5)=(221)^(1//5)`

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