दिया है `m + (1)/(m) = 3`
दोनों ओर का घन करने पर
`(m+(1)/(m))^(3)=(3)^(3)`
`rArr" "(m^(3))+((1)/(m))^(3)+3 xx m xx (1)/(m)(m+(1)/(m))=27`
`rArr" "m^(3)+(1)/(m^(3))+3(m+(1)/(m))=27" "rArr" "m^(3)+(1)/(m^(3))+3(3) = 27`
`rArr" "m^(3) + (1)/(m^(3))=27 - 9 " "rArr" "m^(3)+(1)/(m^(3))=18`