Question

The sum of first three terms of an AP is 48. If the product of first and second terms exceeds 4 times the third term by 12. Find the AP.

Answer 1

Let the first three terms of the AP be (a - d),a and (a + d).

Then (a - d) + a + (a + d) = 48

\(\Rightarrow\) 3a = 48

\(\Rightarrow\) a = 16

Now,

Hence, the first three terms of the AP are 7, 16, and 25.