Given
x2 - 4x - 1 = 0
On comparing it with ax2 + bx + c = 0, we get:
a = 1,
b = - 4
and c = -1
Discriminant D is given by:
D = (b2 - 4ac)
= (-4)2 - 4 x 1 x (-1)
= 16 + 4
= 20
= 20>0
Hence, the roots of the equation are real.
Roots α and β are given by:

Thus, the roots of the equation are (2 + √5) and (2 - √5)