Given
x2 - 6x + 4 = 0
On comparing it with ax2 + bx + c = 0, we get
a = 1, b = - 6 and c = 4
Discriminant D is given by:
D = (b2 - 4ac)
= (-6)2 - 4 x 1 x 4
= 36 - 16
= 20>0
Hence, the roots of the equation are real.
Roots α and β are given by

Thus, the roots of the equation are (3 + 2√5) and (3 - 2√5).