Total number of all possible outcome = 52
(i) Total Number of aces = 4
Therefore, P(getting an ace) = \(\frac{4}{52}\) = \(\frac{1}{13}\)
(ii) Number of 4 of spades = 1
Therefore, P(getting a 4 of spades) = \(\frac{1}{52}\)
(iii) Number of 9 of a black suit = 2
Therefore, P(getting a 9 of a black suit) = \(\frac{2}{52}\) = \(\frac{1}{26}\)
(iv) Number of red kings = 2
Therefore, P(getting a red king) = \(\frac{2}{52}\) = \(\frac{1}{26}\)
