Total number of all possible outcomes = 52
(i) Total number of queen = 4
Therefore, P(getting a queen) = \(\frac{4}{52}\) = \(\frac{1}{13}\)
(ii) Number of diamond suits = 13
Therefore, P(getting a queen) = \(\frac{13}{52}\) = \(\frac{1}{4}\)
(iii) Total number of kings = 4
Let E be the event of getting a king or an ace card.
Then, the favorable outcomes = 4 + 4 = 8
Therefore, P(getting a queen) = P(E) = \(\frac{8}{52}\) = \(\frac{2}{13}\)
(iv) Number of red aces = 2
Therefore, P(getting a queen) = P(E) = \(\frac{2}{52}\) = \(\frac{1}{26}\)
