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The line 2x – y + 4 = 0 cuts the parabola y2 = 8x in P and Q. The mid - point of PQ is :

A. (1, 2) 

B. (1, - 2) 

C. (- 1, 2) 

D. (- 1, - 2)

1 Answer

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Option : (C)

Given that,

The line 2x - y + 4 = 0 cuts the parabola y2 = 8x at P, Q. 

We need to find the midpoint of PQ. 

Substituting y = 2x + 4 in the equation of parabola. 

⇒ (2x + 4)2 = 8x 

⇒ 4x2 + 16x + 16 = 8x 

⇒ 4x2 + 8x + 16 = 0 

⇒ x2 + 2x + 4 = 0 

Let x1, x2 be the roots. 

Then, 

x1 + x2 = - 2 

Now,

Substituting x = \(\frac{y^2}{8}\)in the equation of the line we get,

⇒ y2 - 4y + 16 = 0 

Let y1, y2 be the roots. 

Then, 

y1 + y2 = 4 

Let us assume P be (x1, y1) and Q be (x2, y2) and R be the midpoint of PQ.

⇒ R = (- 1, 2)

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