Number of possible outcomes = 36
Let E be the event of getting two numbers whose product is a perfect square.
Then, the favorable outcomes are (1,1),(1,4),(4,1),(2,2),(3,3),(4,4),(5,5) and (6,6)
The number of favorable outcomes = 8.
Therefore, P(getting numbers whose product is a perfect square) = \(\frac{number\, of\,favorable\,outcomes}{number\,of \,all\,possible\,outcomes}\) = \(\frac{8}{36}\) = \(\frac{2}{9}\)
Thus, the probability of getting such numbers on the dice whose product is a perfect square is \(\frac{2}{9}\).
