When two different dice are thrown, then total number of outcomes = 36.
Let E be the event of getting the product of the numbers, as a perfect square.
These numbers are (1,1),(1,4),(2,2),(3,3),(4,1),(4,4),(5,5) and (6,6)
Number of favorable outcomes = 8
Therefore, p(getting the product of numbers, as a perfect square) = P(E) = \(\frac{number\,of\,outcomes\,favorable\,to\,E}{number\,of\,all\,possible\,outcomes}\) = \(\frac{8}{36}\) = \(\frac{2}{9}\)
Thus, the probability of getting the product of numbers, as a perfect square is \(\frac{2}{9}\).
