Given : \(\frac{(3+2i)^2}{(4-3i)}\)
Firstly, we calculate \(\frac{(3+2i)^2}{(4-3i)}\) and then find its modulus

Now, we rationalize the above by multiplying and divide by the conjugate of 4 + 3i


Now, we have to find the modulus of

Hence, the modulus of \(\frac{(3+2i)^2}{(4-3i)}\) is \(\frac{13}{5}\)