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Find the modulus of each of the following:

\(\frac{(3+2i)^2}{(4-3i)}\)

(3+2i)2/(4-3i)

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Given : \(\frac{(3+2i)^2}{(4-3i)}\)

Firstly, we calculate \(\frac{(3+2i)^2}{(4-3i)}\) and then find its modulus

Now, we rationalize the above by multiplying and divide by the conjugate of 4 + 3i

Now, we have to find the modulus of

Hence, the modulus of \(\frac{(3+2i)^2}{(4-3i)}\) is \(\frac{13}{5}\)

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