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Find the equation of the line whose portion intercepted between the axes is bisected at the point (3, -2).

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To Find: The equation of the line whose portion intercepted between the axes is bisected at the point (3, - 2).

Formula used: Let the equation of the line be

x/a+y/b = 1

Since it is given that this equation, whose portion is intercepted between the axes is bisected i.e.; is divided into ratio 1:1.

Let A(a,0) and B(0,b) be the points foring the coordinate axis.

⟹ a and b are intercepts of x and y -axis respectively.

By using mid-point formula (m:n = 1:1)

Since given point (3 , - 2) divides coordinate axis in 1:1 ratio

(x, y) = (3 , - 2)

- 4x +6y = - 24

- 2x +3y = - 12

Hence the required equation of the line is 2x - 3y = 12.

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