To evaluate \(\lim\limits_{\text x \to0}\left(\cfrac{e^{4\text x}-1}{\text x}\right)
\)
lim(x→0) (e4x - 1)/x
Formula used: L'Hospital's rule
Let f(x) and g(x) be two functions which are differentiable on an open interval I except at a point a where

This represents an indeterminate form. Thus applying L'Hospital's rule, we get

Thus, the value of \(\lim\limits_{\text x \to0}\left(\cfrac{e^{4\text x}-1}{\text x}\right)
\) is 4.