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Three unbiased coins are tossed once. Find the probability of getting at most 2 tails or at least 2 heads

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Best answer

We know that,

Probability of occurrence of an event

  = \(\frac{Total\,no.of\,Desired\,outcomes}{Total\,no.of\,outcomes}\) 

Let T be tails and H be heads 

Total possible outcomes = TTT, TTH, THT, HTT, THH, HTH, HHT, HHH 

Desired outcomes are at least two heads or at most two tails. So, desired outputs are TTH, THT, HTT, THH, HTH, HHT, HHH 

Total no. of outcomes are 8 and desired outcomes are 7 

Probability of getting at most 2 tails or at least 2 heads = \(\frac{7}{8}\)

Conclusion: Probability of getting at least two heads or at most two tails is  \(\frac{7}{8}\) 

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