Given: sinx = \(-\frac{1}{2}\) and x lies in Quadrant IV.
To Find:
(i) sin\(\frac{x}{2}\)
(ii) cos\(\frac{x}{2}\)
(iii) tan\(\frac{x}{2}\)
Now, since sinx = \(-\frac{1}{2}\)
We know that cosx = \(\pm\sqrt{1-sin^2\text{x}}\)
since cosx is positive in IV quadrant, hence cosx \(\frac{\sqrt{3}}{2}\)
(i) sin\(\frac{x}{2}\)
Formula used:
Since sinx is negetive in IV quadrant, hence sin\(\frac{x}{2}=-\frac{\sqrt{2-\sqrt{3}}}{2}\)
(ii) cos\(\frac{x}{2}\)
Formula used:
(iii) tan\(\frac{x}{2}\).
Formula used:
tanx = \(\frac{sinx}{cosx}\)