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in Linear Equations by (55.0k points)
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If (A - 2B) = \( ​​​​\begin{pmatrix} 1 & -2 \\ 3 & 0 \\ \end{pmatrix} \)and (2A-3B) = \( ​​​​\begin{pmatrix} -2 & 2 \\ 3 & -3 \\ \end{pmatrix} \) then B = ?

A. \( ​​​​\begin{pmatrix} 6 & -4 \\ -3 & 3 \\ \end{pmatrix} \)

B. \( ​​​​\begin{pmatrix} -4 & 6 \\ -3 & -3 \\ \end{pmatrix} \)

C. \( ​​​​\begin{pmatrix} 4 & -6 \\ 3 & -3 \\ \end{pmatrix} \)

D. none of these

1 Answer

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Best answer

Correct answer is B \( ​​​​\begin{pmatrix} -4 & 6 \\ -3 & -3 \\ \end{pmatrix} \)

(A - 2B) = \( ​​​​\begin{pmatrix} 1 & -2 \\ 3 & 0 \\ \end{pmatrix} \)

Multiplying equation by 2

\( ​​​​\begin{pmatrix} -4 & 6 \\ 3 & -3 \\ \end{pmatrix} \)

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