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+3 votes
8.8k views
in Mathematics by (15.9k points)

Let f: R → R be defined as

f(x) = \(\begin{cases} \frac{\lambda|x^2 -5x +6|}{\mu|5x-x^2 -6} , & \quad x<2\\ e^{\frac{tan(x-2)}{x-|x|}}, & \quad x>2\\ \mu, & \quad x=2 \end{cases}\)

Where [x] is the greatest integer less than or equal to x. If f is continuous at x = 2, the \(\lambda\) + \(\mu\) is equal to :

(1) e(-e + 1)

(2) e(e - 2)

(3) 1

(4) 2e -1

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1 Answer

+3 votes
by (15.3k points)

Correct option (1) e(-e + 1)

\(\lambda\) + \(\mu\) = e(–e + 1)

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