The correct option is (C) 26
Explanation:
We have to expand (x + a)51 – (x – a)51
At first, (x + a)51 = 51C0 x51 + 51C1 x50 . a + 51C2 x49 . a2 + ...... + 51C51 a51
then, (x – a)51 = 51C0 x51 - 51C1 x50 . a + 51C2 x49 . a2 - ...... - 51C51 a51
When we subtract both the values i.e. (x + a)51 – (x – a)51 we get,
2( 51C1 x50 . a + 51C3 x48 . a3 + ...... + 51C51 a51)
Thus count the number of terms that is number of odd numbers up to 51.
i.e 1, 3, 5, 7, ......, 49, 51
Apply AP:
a + (n-1)d = 51
1 + (n-1)2 = 51
n = 26
So, the total numbers of terms in the expansion is 26.