Given : Let u = log x and v = cot x
To differentiate : log xwith respect to cot x
Formula used :
The CHAIN RULE states that the derivative of f(g(x)) is f’(g(x)).g’(x)
Let u = log x and v = cot x
Differentiating u with respect to x
\(\cfrac{du}{d\text x}=\cfrac1{\text x}\)
Differentiating v with respect to x
