Given : Let u = esin x and v = cos x
To differentiate : esin x with respect to cos x
Formula used : \(\cfrac{d(e^{\text x})}{d\text x}=e^{\text x}\)
\(\cfrac{d(cos\,\text x)}{d\text x}=-sin\,\text x\)
The CHAIN RULE states that the derivative of f(g(x)) is f’(g(x)).g’(x)