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Differentiate esin x with respect to cos x.

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Given : Let u = esin x and v = cos x

To differentiate : esin x with respect to cos x

Formula used : \(\cfrac{d(e^{\text x})}{d\text x}=e^{\text x}\)

\(\cfrac{d(cos\,\text x)}{d\text x}=-sin\,\text x\)

The CHAIN RULE states that the derivative of f(g(x)) is f’(g(x)).g’(x)

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