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If AD and PM are medians of triangles ABC and PQR, respectively where`DeltaA B C ~DeltaP Q R`, prove that `(A B)/(P Q)=(A D)/(P M)`

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If AD and PM are medians of triangles ABC and PQR, respectively where`DeltaA B C ~DeltaP Q R`, prove that `(A B)/(P Q)=(A D)/(P M)`
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from diagram
BD=DC=1/2BC and QM=MR=1/2QR
there ratio should also be same
`(BD)/(QM)=(BC)/(QR)=(AB)/(PQ)-(1)`
`/_ABD~/_PQM -(2)`(SAS)
from 1 and 2
`(AD)/(PM)=(AB)/(PQ)=(BP)/(QM)`
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