Data : AD and PM are medians of triangles ∆ABC and ∆PQR respectively. ∆ABC ~ ∆PQR.
To Prove:\(\frac{AB}{PQ} = \frac{AD}{PM}\)
∆ABC ~ ∆PQR.(data)
∴ we have
\(\frac{AB}{PQ} = \frac{AC}{PR} = \frac{BC}{QR}\)
D is the mid-point of BC. BD = DC.
M Is the mid-point of QR. QM = MR
∴ \(\frac{BC}{QR} = \frac{BD}{QM}\)
In ∆ABD and ∆PQM, we have
