Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
166 views
in Polynomials by (71.6k points)
closed by
If the product of the zero of the polynomial `(ax^2 - 6x - 6)` is 4. Find the value of a.

1 Answer

0 votes
by (71.7k points)
selected by
 
Best answer
Let `alpha and beta` be the zeros of the polynomial `(ax^(2) - 6x - 6)`.
Then, alpha beta =` ("constant term ")/("coefficient of " x^(2)) = (-6)/a.`
But, `alpha beta = 4` (given).
Hence, ` a=(-3)/2.`

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...