Question

Two batteries of emf 3V and 6V with internal resistances 2Ω and 4Ω are connected in a circuit with resistance of 10Ω as shown in the figure. The current and potential difference between the points P and Q are

(a) 3/16 A and 8/15 V

(b) 16/3 A and 15/8 V

(c) 3/16 A and 8 V

(d) 3/16 A and 15/8 V

Answer 1

Answer is : (d) 3/16 A and 15/8 V

Applying Kirchhoff’s voltage law in the given loop.

∵ Potential difference across

PQ = 3/16 x 10 = 15/8 V