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in Continuity and Differentiability by (35.1k points)

Function \(f(x) = \begin{cases} \frac{x^2 - 4x + 3}{x^2 - 1}, & \quad x\neq 1\\ 2, & \quad x=1 \end{cases},\) is

f(x) = {(x2 - 4x + 3)/(x2 - 1), x ≠ 1, 2, x = 1 is

(A) continuous at x = 1.

(B) continuous at x = -1.

(C) continuous at x = 1 and x = -1.

(D) discontinuous at x = 1.

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1 Answer

+1 vote
by (31.4k points)

Correct answer is

(D). discontinuous at x = 1.

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