Correct Answer - The given sequence is an A.P.
Here, `t_(1) = (3)/(2), t_(2) = (1)/(2), t_(3) = - (1)/(2)`
`t_(4) = - (3)/(2),….`
`t_(2) - t_(1) - (1)/(2) - (3)/(2) =(1-3)/(2) = ( - 2)/(2) = -1 `
`t_(3) - t_(2) = - (1)/(2) - (1)/(2) = ( - 1-1)/(2) = ( - 2)/(2) = - 1 `
` t_(4) - t_(3) = - (3)/(2)- (-(1)/(2)) = - (3)/(2) + (1)/(2) = ( - 3+1)/(2) = ( -2)/(2) = -1`
The common difference between any two consecutive terms `( d= - 1)` is constant
