Fewpal
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The inner diameter of a cylindrical wooden pipe is 24 cm and its outer diameter is 28 cm. The length of the pipe is 35 cm. Find the mass of the pipe, if 1 cm3 of wood has a mass of 0.6 g. 

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Here, inner radius (r) = 24/ 2 cm = 12 cm 

Outer radius (R) = 28/ 2 cm = 14 cm, h = 35 cm 

Volume of the wood used in the pipe = π(R2 – r2) h 

= 22/ 7 [(14)4 – (12)2] × 35 cm3 

= 22/ 7 × 26 × 2 × 35 cm3 = 5720 cm

Mass of 1 cm3 of wood = 0.6 g 

∴ Mass of 5720 cm3 of wood = 0.6 × 5720 g = 3432 g = 3.432 kg Ans.

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