Solution:
Given, radius of the base of the bucket = 18 cm
Height of the bucket = 32 cm ‘
So, volume of the sand in cylindrical bucket = πr2h= π (18)2 x 32 = 10368 π
Also, given height of the conical heap (h) = 24 cm
Let radius of heap be r cm.
According to the question,
Volume of the sand in cylindrical bucket = Volume of the sand in conical heap
Hence, radius of conical heap of sand = 36 cm
and slant height of conical heap = 43.267 cm