**Solution : **

Given: Two resistors with resistances R1=5ohm and R2=10ohm, V=6volt

(a) For minimum current these two should be connected in series. For maximum current these two should be connected in parallel.

(b)In series,

Total resistance = 5+10 = 15ohms

Therefore total current drawn = V/R = 6/15 = 0.4amps

In parallel,

Total resistance R is given as 1/R=1/R_{1}+1/R_{2}

1/R =1/5+1/10

1/R=3/10

R=10/3 ohm

Therefore total current drawn by the circuit = V/R = 6/(10/3) =1.8amps.