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You are requested to make 20 moles of NaCl into packets of 100g each. (Hint Molecular mass of NaCl is 58.5) 

a. How many packets of NaCl can be prepared? 

b. Is there any NaCl remaining? If so, how much?

1 Answer

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a. Mass of 20 mol NaCl = 20 × 58.5 = 1170g 

1170 g NaCl can be made into 11 packets with 100g each. 

b. Remaining NaCl = 1170 – 1100 = 70g

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