Question

The chemical equation of the decomposition of calcium carbonate is given below. 

CaCO₃ → CaO + CO₂ 

(Hint MM: CaCO₃ – 100, CaO – 56, CO₂  – 44) 

a. Calculate the mass of CaCO₃ required to get 224 g of CaO? 

b. Calculate the number of CO₂ molecules fronted when 224g of CaO is obtained?

Answer 1

a. CaCO₃ → CaO + CO₂

100g 56g 44g 

I I : I 

Amount of CaCO₃ required to get 56g of CaO = 100g

Amount of CaCO₃ required to get 1 g of CaO = \(\frac{100}{56}\) 

Amount of CaCO₃ required to get 224 g of CaO = \(\frac{100}{56}\times224\) = 400g

b. 4 × 6.022 × 10²³