Question

`1.0 mol` of pure dinitrogen gas at `SATP` conditions was put into a vessel of volume `24.8 m^(3)` maintained at the temperature of `596.3 K`. What is the pressure of the gas in the vessel?

Answer 1

Volume of `1.0 mol` of a gas at `SATP(V_(1))=24.8xx10^(-3)m^(-3)`
`{:("Initial conditions(SATP)","Final conditions"),(V_(1)=24.8xx10^(-3)m^(3)m, V_(2)=24.8m^(3)),(P_(1)=1 "bar", P_(2)=?),(T_(1)=298.15 K,T_(2)=596.3 K):}`
According to the gas equation,
`(P_(1)V_(1))/(T_(1))=(P_(2)V_(2))/(T_(2))`
or `P_(2)=(P_(1)V_(1)xxT_(2))/(T_(1)xxV_(2))=(1.0xx24.8xx10^(-3)xx596.3)/(298.15xx24.8)`
`=2xx10^(-3)` bar
`:. P_(2)=2xx10^(-3)`bar