Question

`20 mL of 0.2MAl_(2)(SO_(4))_(3)` mixed with `20 mL` of `0.6M BaCl_(2)`. Calculate the concentration of each ion in solution.

Answer 1

`Al_(2) (SO_(4))_(3) + BaCl_(3) + BaCl_(2) rarr BaSO_(4) darr + AlCl_(3)`
mEq before `20 xx 0.2 xx 6` `20 xx 0.6 xx 2` 0 0
mEq after 0 0 24 24
mixing
mEq `= M xx V` (in `mL`) `M xx` Valency
`:. [Al^(3+)] = (24)/(40 xx 3) = 0.2 M`
Total volume `= 20 + 20 = 40 mL`
`[Cl^(ɵ) = 0.6 M`
No concentration of `Ba^(2+)` or `SI_(4)^(2-)` in the solution since `BaSO_(4)` gets precipitated.