Question

`20 mL of 0.2MAl_(2)(SO_(4))_(3)` mixed with `20 mL` of `0.6M BaCl_(2)`. Calculate the concentration of each ion in solution.

Answer 1

`{:(,Al_(2)(SI_(4))_(3)+,BaCl_(2)rarr,BaSO_(4)darr+,AlCl_(3)),("Meq. before",20xx0.2xx6,20xx0.6xx2,,),("mixing",=24,=24,0,0),("Meq. after mixing",0,0,24,24):}`
`(Meq. = NxxV "in"mL=Mxx"valency"xxV"in" mL)`
`:. [Al^(3+)]=(24)/(40xx3)=0.2M`
`[Cl^(-)]=(24)/(40)=0.6M`
No concentration of `Ba^(2+)` or `SO_(4)^(2-)` in solution since `BaSO_(4)` gets precipitated.